abhas
Active member
 |  Subject: LOGIC based question Fri Dec 14, 2007 12:00 pm | |
| | Place 21 jewels in 4 boxes such that each box contains an odd number of jewels? |
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abhas
Active member
| | Subject: answer Fri Dec 14, 2007 12:01 pm | |
| answer
place 7 in each of 3 smallest boxes.
put all 3 boxes in the biggest box.
there's 7,7,7 and 21, all odd |
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amydecia
Active member
| | Subject: Re: LOGIC based question Fri Apr 29, 2011 2:29 pm | |
| The answer is not coming in 4 different odd number. In three number we can do it 7,7,7 = 21.
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