Uber Active member
| Subject: whtz the right method to solve Wed Mar 17, 2010 2:56 pm | |
| verify
sigma(0,1,5,6)=pie(2,3,4,7). |
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NITIN BHUWANIA Active member
| Subject: Re: whtz the right method to solve Wed Mar 17, 2010 3:15 pm | |
| USING KARNAUGH MAP.. GET THE MINTERMS USING KARNAUGH MAP AND REDUCE IT ACCORDING TO THE LAWS.(DO THIS FOR BOTH SIDES SEPARATELY)
AT LAST U WILL GET THE LEFT SIDE SAME AS THE RIGHT SIDE...
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Uber Active member
| Subject: Re: whtz the right method to solve Wed Mar 17, 2010 3:36 pm | |
| but one will be POS and the other will be SOP exp.......do we hav to simplfy them also ?????? |
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NITIN BHUWANIA Active member
| Subject: Re: whtz the right method to solve Wed Mar 17, 2010 5:22 pm | |
| u have to apply the concept of map rolling over here... |
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WinRrule Active member
| Subject: Re: whtz the right method to solve Wed Mar 17, 2010 6:10 pm | |
| do it using truth table..! |
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RC Active member
| Subject: Re: whtz the right method to solve Wed Mar 17, 2010 6:56 pm | |
| this is a q from the specimen paper |
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NITIN BHUWANIA Active member
| Subject: Re: whtz the right method to solve Wed Mar 17, 2010 8:45 pm | |
| the complement of sigma(0,1,5,6)=sigma(2,3,4,7)
and the complement of pie(2,3,4,7)=pie(2,3,4,7)
therefore they are equal..
i m not very much sure about the method... i got it from one of the books where the spcimen paper was solved.
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NITIN BHUWANIA Active member
| Subject: Re: whtz the right method to solve Wed Mar 17, 2010 8:45 pm | |
| do a cross check with your subject teacher.. |
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G-7 Active member
| Subject: Re: whtz the right method to solve Wed Mar 17, 2010 9:29 pm | |
| just like WinRule said..use the form the truth table...prove both are 'contingencies'..!! |
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Uber Active member
| Subject: Re: whtz the right method to solve Thu Mar 18, 2010 12:41 am | |
| winrule is right......but how can we use map rolling...?? |
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| Subject: Re: whtz the right method to solve | |
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