Simple Word problem maths

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1)Ann walks 5km in 1 hour,and betty walks 4km in 1 hour.If they start
walking toward each other fom a distrance of 36km,How many hours willl
it take for them to meet?
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2)Denny walks 60 m in 1 minute,and john travels 210 m in 1 minute by bike.
if denny has already walked 1800 m,how many minutes will it tkae for
john to catch up with denny by bike assuming denny continues to walk?

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Subject: Re: Simple Word problem maths Thu Feb 14, 2008 6:34 pm

let ann cover a distance of x Speed of ann =5kmph
then betty covers a distance of (36-x) Speed of Betty=4kmph

Timetaken by ann=x/5
Time taken by betty=(36-x)/3
Timetaken by ann=Time taken by betty
x/5=(36-x)/3
On solving x=50/3
By substituting in A
Time=3.33 hours