Midhun Sarath
Active member
 |  Subject: HELP !!!!!!!!!! URGENT !!!!! Thu Mar 12, 2009 9:40 pm | |
| Q)..Steam at 100^C is passsed through a hole drilled in a 2kg of ice at 0^c.After some time, 1.5kg at ice is left and 562.5g of water at 0^ C is formed. Calculate the specific latent heat of vaporization of water ?????
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Midhun Sarath
Active member
| | Subject: Re: HELP !!!!!!!!!! URGENT !!!!! Thu Mar 12, 2009 10:17 pm | |
| | please help .. some 1 |
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QUEST
Active member
| | Subject: Re: HELP !!!!!!!!!! URGENT !!!!! Fri Mar 13, 2009 2:07 am | |
| m of ice = 2 kg, left ice = 1.5 kg, melted ice = 500 g
total water at 0 degree = 562.5 g----- a
water fm ice = 500 g ---- b
=> water at 0 degree from steam = a - b = 62.5.
heat lost by steam = heat gained by ice
m steam * L steam + m steam *c WATER* DT WATER FRM STEAM=
m ice * L of ice
62.5* L + 62.5 * 4.2* 100 = 500 *336
L OF STEAM = (168000 - 26250 )/ 62.5 = 2268 J/g |
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QUEST
Active member
| | Subject: Re: HELP !!!!!!!!!! URGENT !!!!! Fri Mar 13, 2009 2:23 am | |
| BUT LATENT HEAT OF VAPOURISAION NOT IN SYLLABUS FOR 2009.
ONLYYYYYYYY LATENT HEAT OF FUSION IS THEREIN SYLLABUS |
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| | Subject: Re: HELP !!!!!!!!!! URGENT !!!!! | |
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