implementation of address

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Can anyone help me solve this question:::::

Each element of an array arr[15][20] requires 'W' bytes of storage.If the address of arr[6][8] is4580 and the base address at arr[1][1] is 4000,find the width 'W' of each cell in the array arr[][] when the array is stored as Column major wise.

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i get the answer as 5

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bt how plz can u explain..........

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btw is that answer correct..?? i am not sure if its correct.. as i cannot recollect any variable type having 5 bytes

do u have the anser.?

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no actually it is from isc specimen paper..
it dont hv answers

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anyway i did it using the formula:

Address [i][j] = B + w[r(j-Lc)+(i-Lr)]

[i][j] --> address of element to be found
r --> num of rows Uc-Lc+1
Uc --- upper column limit (here Cool

Lc---lowr column limit (here 1)

Ur---upper row lim (here 6)
Lr---lower row limit (here 1)

B---base address

w --- the space req of the array type (here to be found)

anyone else plz post answers too. Btw what did u gt.?

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what have u taken as no of rows???????
(r)

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r --> num of rows Uc-Lc+1

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no i want to ask the value that u hv taken in this question

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15..??

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plz someone help!!!!!!!!!!

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yup...the answer is 5... Very Happy

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but wait UberSoldat, can u think of any data type which has the capacity 5..? Int is 4, char is 1 float and double are greater than 5..! I doubt if there is some technical problem in the question.....