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Circle question

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PostSubject: Circle question question - Circle question EmptyMon Aug 06, 2007 6:01 pm

pale


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PostSubject: SOLLUTION question - Circle question EmptyFri Aug 10, 2007 1:14 pm

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PostSubject: Re: Circle question question - Circle question EmptySat Jan 24, 2009 2:10 pm

Join QOA and QO'B, then triangle QAB is formed.
Now, OQ=AO (radius of the same circle)
also, O'Q=BO' (radius of same circle)
So, by mid-point theorem, OO'=1/2 of AB
moreover, if POC and PO'D is joined, it will be seen that OO'=1/2 of CD
So, AB=CD..... Smile Smile Smile
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